Question

Two joggers set out at the same time from their homes 24 miles apart. They agree to meet at a point

somewhere in between in an hour and a half. If the rate of one is 6 mph faster than the rate of other,
find the rate of each.

Answer 1

Try reading it over

Explanation:

Answer 2

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Answer:

5 mph, 11 mph

Explanation:

Together, they cover 24 miles in 1.5 hours, so their total rate of speed is ...

(24 mi)/(1.5 h) = 16 mi/h

If s is the rate of the slower jogger, then s+6 is the rate of the faster one. Their total speed is ...

s + (s+6) = 16

2s = 10 . . . . . . . subtract 6

s = 5 . . . . . . . . . divide by 2

s+6 = 11

The rates of the joggers are 5 mph and 11 mph.