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Find the equation of the line parallel to Y=-2x-5 that include the point (-1,3)

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Answer:

Explanation:

To find the answer, we will use the point slope form, since we have both a slope (for 2 lines to be parallel, they must have the same slope, so if the original equation's slope is -2, so will our new one), and we have a point, (-1,3). So lets plug in the values together to the point slope equation (y-y1)=m(x-x1), where x1 and y1 are our "initial" x and y values, or well our desired point, in this case (-1,3), and m is just slope. So now, it'll be

y-(3)= -2(x-(-1)). First, we will apply the signs accordingly, remember 2 negatives make a positive, so y-3= -2(x+1). Now we will multiply so we will have it in slope intercept form, and we can do the last step after of isolating y.

y-3= -2x-2, and now add 3 to both sides, and now the final equation will be

y= -2x+1 !

User Shannon Kendrick
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