Question

When the smaller of two consecutive integers is added to five times the larger, the result is 71

Answer 1

11 and 12

Explanation:

Let the smaller integer be x.

Then the next larger consecutive integer is x + 1.

x + 5(x + 1) = 71

x + 5x + 5 = 71

6x + 5 = 71

6x = 66

x = 11

x + 1 = 11 + 1 = 12

Answer: The integers are 11 and 12.