Question

The weights of canisters of oatmeal are normally distributed with a mean of 1280 grams and a standard deviation of 12 grams.

What percent of the canisters of oatmeal weigh less than 1268 grams?
A: 13.5%
B: 2.5%
C: 0.15%
D: 16%

Answer 1

Explanation:

To find the percentage of canisters weighing less than 1268 grams, we need to calculate the z-score and then use a standard normal distribution table.

The z-score formula is: (X - μ) / σ, where X is the value we want to find the percentage for, μ is the mean, and σ is the standard deviation.

Using the given values:

X = 1268 grams

μ = 1280 grams

σ = 12 grams

Calculating the z-score:

z = (1268 - 1280) / 12 = -1

Looking up the z-score in the standard normal distribution table, we find that the percentage is approximately 0.1587, which is closest to option C: 0.15%.