Question

Evaluate the function when x =-2,0,and 5

Answer 1

x = 5, p(x) is equal to -1.75.

Explanation:

To evaluate the function p(x) = -3 + 1/4x when x = -2, 0, and 5, we substitute these values into the function and simplify the expression.

1. Evaluating p(x) when x = -2:

p(-2) = -3 + 1/4(-2)

= -3 - 1/2

= -3 - 0.5

= -3.5

Therefore, when x = -2, p(x) is equal to -3.5.

2. Evaluating p(x) when x = 0:

p(0) = -3 + 1/4(0)

= -3 + 0

= -3

So, when x = 0, p(x) is equal to -3.

3. Evaluating p(x) when x = 5:

p(5) = -3 + 1/4(5)

= -3 + 5/4

= -3 + 1.25

= -1.75

Thus, when x = 5, p(x) is equal to -1.75.

In summary:

- When x = -2, p(x) = -3.5

- When x = 0, p(x) = -3

- When x = 5, p(x) = -1.75

These are the values of the function p(x) when x is equal to -2, 0, and 5, respectively.

Answer 2

`\sf -(7)/(2), \: -3, \textsf{ and } -(7)/(4), \textsf{respectively}`

Explanation:

Given function:

`p(x) = -3 +(1)/(4)x`

To evaluate the function

when x =-2, 0, and 5

Solution:

To evaluate the function, we simply substitute the values of x into the function and evaluate.

When x = -2, we get:

`\sf p(-2) = -3 + (1)/(4)(-2) = -3 - (1)/(2) = -(7)/(2)`

When x = 0, we get:

`\sf p(0) = -3 + (1)/(4)(0) = -3`

When x = 5, we get:

`p(5) = -3 + (1)/(4)(5) = -3 + (5)/(4) = -(7)/(4)`

Therefore, the values of the are:

`\sf -(7)/(2), \: -3, \textsf{ and } -(7)/(4), \textsf{respectively}`