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What is the equation of the line that passes through the point(8,1) and has a slope of -3/4 ​ ?

User Jdhao
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Answer:

Explanation:

To find the equation of the line that passes through the point (8, 1) and has a slope of -3/4, you can use the point-slope form of the equation of a line:

y - y1 = m(x - x1)

Where:

- (x1, y1) is the given point (8, 1).

- m is the slope (-3/4).

Now, plug in the values:

y - 1 = (-3/4)(x - 8)

Next, distribute the slope (-3/4) to both terms inside the parentheses:

y - 1 = (-3/4)x + (3/4)(8)

Now, simplify:

y - 1 = (-3/4)x + 6

To isolate y, add 1 to both sides of the equation:

y = (-3/4)x + 6 + 1

y = (-3/4)x + 7

So, the equation of the line passing through the point (8, 1) with a slope of -3/4 is:

y = (-3/4)x + 7

User John Dorian
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