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Find the value of A so that the line given by Ax+10y=20 has an x-intercept of -5.

2 Answers

4 votes

Answer:


A=-4

Step-by-step explanation:

Given: x-intercept of -5 |
ax+10y=20

Find value of
a

To find the x-intercept of a line, you set
y=0 and solve for
x

1.) Substiute
y=0 and
x=-5 into the equation
ax+10y=20


A(-5)+10(0)=20

2.) Multiply/Simplify


-5A=20

3.) Divide by -5 on both sides to solve for
A


A=-4

User Razzupaltuff
by
9.1k points
2 votes

Final answer:

To find the value of A so that the line has an x-intercept of -5, substitute -5 for x in the equation and solve for A. The value of A is -4.

Step-by-step explanation:

To find the value of A so that the line has an x-intercept of -5, we need to substitute -5 for x in the equation and solve for A.

Substituting -5 for x in the equation Ax+10y=20, we get: A(-5)+10y=20.

Simplifying the equation gives us: -5A+10y=20.

Since we know that the x-intercept occurs when y is zero, we can solve the equation for A when y is zero. Substitute 0 for y in the equation: -5A+10(0)=20.

Simplifying further gives us: -5A=20.

Dividing both sides of the equation by -5, we find: A=-4.

User Sanis
by
8.4k points

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