Question

Find the value of A so that the line given by Ax+10y=20 has an x-intercept of -5.

Answer 1

`A=-4`

Step-by-step explanation:

Given: x-intercept of -5 |
`ax+10y=20`

Find value of
`a`

To find the x-intercept of a line, you set
`y=0` and solve for
`x`

1.) Substiute
`y=0` and
`x=-5` into the equation
`ax+10y=20`

`A(-5)+10(0)=20`

2.) Multiply/Simplify

`-5A=20`

3.) Divide by -5 on both sides to solve for
`A`

`A=-4`

Answer 2

To find the value of A so that the line has an x-intercept of -5, substitute -5 for x in the equation and solve for A. The value of A is -4.

Step-by-step explanation:

To find the value of A so that the line has an x-intercept of -5, we need to substitute -5 for x in the equation and solve for A.

Substituting -5 for x in the equation Ax+10y=20, we get: A(-5)+10y=20.

Simplifying the equation gives us: -5A+10y=20.

Since we know that the x-intercept occurs when y is zero, we can solve the equation for A when y is zero. Substitute 0 for y in the equation: -5A+10(0)=20.

Simplifying further gives us: -5A=20.

Dividing both sides of the equation by -5, we find: A=-4.