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The equation 2x2 - 8x = 10 is rewritten in the form of 2(x-p)2+ q = 0. What is the value of q?

-2

18

-18

2

User AceBox
by
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2 Answers

7 votes

Answer: The given quadratic equation is 2x² - 8x = 10. We can rewrite this equation in the form of 2(x-p)² + q = 0. Comparing the two equations, we can see that:

a = 2 b = -8 c = -10

We know that the vertex form of a quadratic equation is a(x-h)² + k, where (h,k) is the vertex of the parabola. We can convert the given equation to vertex form by completing the square:

2x² - 8x = 10 2(x² - 4x) = 10 2(x² - 4x + 4 - 4) = 10 2((x-2)² - 4) = 10 (x-2)² - 4 = 5 (x-2)² = 9

Therefore, the vertex of the parabola is (2,-4). Since the parabola opens upwards, its minimum value is at the vertex. Thus, q is equal to the minimum value of the parabola, which is -4.

Therefore, the value of q in the equation 2(x-p)² + q = 0 is -4.

User Yotsov
by
7.0k points
1 vote

Answer:

Hi,

-18

Explanation:


2x^2-8x=10\\\\x^2-4x=5\\\\x^2-4x-5=0\\\\x^2-4x+4-4-5=0\\\\(x-2)^2-9=0\\\\2(x-2)^2-18=0\\\\\boxed{q=-18}\\

User Renato Vitolo
by
8.1k points