80.1k views
5 votes
The equation 2x2 - 8x = 10 is rewritten in the form of 2(x-p)2+ q = 0. What is the value of q?

-2

18

-18

2

User AceBox
by
8.2k points

2 Answers

7 votes

Answer: The given quadratic equation is 2x² - 8x = 10. We can rewrite this equation in the form of 2(x-p)² + q = 0. Comparing the two equations, we can see that:

a = 2 b = -8 c = -10

We know that the vertex form of a quadratic equation is a(x-h)² + k, where (h,k) is the vertex of the parabola. We can convert the given equation to vertex form by completing the square:

2x² - 8x = 10 2(x² - 4x) = 10 2(x² - 4x + 4 - 4) = 10 2((x-2)² - 4) = 10 (x-2)² - 4 = 5 (x-2)² = 9

Therefore, the vertex of the parabola is (2,-4). Since the parabola opens upwards, its minimum value is at the vertex. Thus, q is equal to the minimum value of the parabola, which is -4.

Therefore, the value of q in the equation 2(x-p)² + q = 0 is -4.

User Yotsov
by
7.7k points
1 vote

Answer:

Hi,

-18

Explanation:


2x^2-8x=10\\\\x^2-4x=5\\\\x^2-4x-5=0\\\\x^2-4x+4-4-5=0\\\\(x-2)^2-9=0\\\\2(x-2)^2-18=0\\\\\boxed{q=-18}\\

User Renato Vitolo
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories