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Solve the inequality x^3 9x^2-10x>0

User Xeofus
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1 Answer

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Explanation:

To solve the inequality \(x^3 - 9x^2 - 10x > 0\), you can follow these steps:

1. First, factor the expression:

\(x(x^2 - 9x - 10) > 0\)

2. Now, factor the quadratic expression inside the parentheses:

\(x(x - 10)(x + 1) > 0\)

3. Determine the critical points by setting each factor equal to zero and solving for \(x\):

\(x = 0\)

\(x - 10 = 0 \implies x = 10\)

\(x + 1 = 0 \implies x = -1\)

4. Create a sign chart using these critical points:

- On the left of -1, all factors are negative.

- Between -1 and 0, \(x\) is positive, but \((x - 10)\) and \((x + 1)\) are negative.

- Between 0 and 10, all factors are positive.

- To the right of 10, \(x\) and \((x - 10)\) are positive, but \((x + 1)\) is negative.

5. Now, determine the sign of the expression \(x(x - 10)(x + 1)\) in each interval:

- Left of -1: Negative * Negative * Negative = Negative

- Between -1 and 0: Positive * Negative * Negative = Positive

- Between 0 and 10: Positive * Positive * Positive = Positive

- Right of 10: Positive * Positive * Negative = Negative

6. The inequality \(x^3 - 9x^2 - 10x > 0\) is satisfied when the expression \(x(x - 10)(x + 1)\) is greater than zero, which occurs in the intervals where it is positive.

So, the solution to the inequality is:

\(x < -1\) or \(0 < x < 10\)

These are the values of \(x\) for which the original inequality is true.

User BCLtd
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