105k views
5 votes
ver True or False. Suppose the square of f varies directly with the cube of p and inversely with m, and when f=2, p=1, and m=3, f² = 10 p³/m : TRUE FALSE

1 Answer

5 votes

Final answer:

The statement is true. The square of f varies directly with the cube of p and inversely with m.

Step-by-step explanation:

True

The statement is true. The square of f varies directly with the cube of p and inversely with m can be represented as:

f² = k(p³/m)

Using the given values f = 2, p = 1, and m = 3, we can substitute them into the equation:

2² = k(1³/3)

Simplifying, we get:

4 = k(1/3)

Dividing both sides by 1/3, we get:

4/(1/3) = k

12 = k

Therefore, the equation becomes:

f² = 12(p³/m)

So, when f = 2, p = 1, and m = 3, we have f² = 12(1³/3) = 12(1/3) = 4.

Hence, the statement is TRUE.

Learn more about Direct and inverse variation

User JeremyS
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.