Question

A 25.0-g silver block initially at 27.0 °C absorbs 2.38 kJ of heat. What is the final

temperature (in °C) of the silver? The specific heat capacity of silver is 0.235 J/(g•°C)

Answer 1

To find the final temperature of the silver block, you can use the formula for heat transfer:

Q = m x c x change in temperature

I have solved it and fully explained in the attached image :)