183k views
1 vote
F(y) is inversely proportional to x2 and y=5 when x=4, find the value of y when x=2.

User JeffH
by
7.5k points

1 Answer

2 votes

In this problem, we are given that F(y) is inversely proportional to x^2. We also know that when y = 5, x = 4. We need to find the value of y when x = 2.

1. If F(y) is inversely proportional to x^2, it means that F(y) = k/x^2, where k is a constant.

2. We can find the value of k using the given information. When y = 5 and x = 4:

- F(5) = k/4^2

- F(5) = k/16

3. To solve for k, we can multiply both sides of the equation by 16:

- F(5) * 16 = k

- 5 * 16 = k

- k = 80

4. Now that we have the value of k, we can find F(y) for any given value of x. In this case, we need to find F(y) when x = 2:

- F(y) = 80/2^2

- F(y) = 80/4

- F(y) = 20

5. Therefore, when x = 2, the value of y is 20.

So, when x = 2, y = 20.

User Bublik
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories