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F(y) is inversely proportional to x2 and y=5 when x=4, find the value of y when x=2.

User JeffH
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In this problem, we are given that F(y) is inversely proportional to x^2. We also know that when y = 5, x = 4. We need to find the value of y when x = 2.

1. If F(y) is inversely proportional to x^2, it means that F(y) = k/x^2, where k is a constant.

2. We can find the value of k using the given information. When y = 5 and x = 4:

- F(5) = k/4^2

- F(5) = k/16

3. To solve for k, we can multiply both sides of the equation by 16:

- F(5) * 16 = k

- 5 * 16 = k

- k = 80

4. Now that we have the value of k, we can find F(y) for any given value of x. In this case, we need to find F(y) when x = 2:

- F(y) = 80/2^2

- F(y) = 80/4

- F(y) = 20

5. Therefore, when x = 2, the value of y is 20.

So, when x = 2, y = 20.

User Bublik
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