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Find all the three angles of the ABC angle A=(x+35)°, B=(2x-5)°, C=(4x-15)°​

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Answer:

Angle A = 58.57°

Angle B = 42.14°

Angle C = 80.29°

Explanation:

To find the three angles of triangle ABC, we need to set up an equation using the given angle measures.

Angle A is given as (x+35)°, angle B is given as (2x-5)°, and angle C is given as (4x-15)°.

According to the angle sum property of a triangle, the sum of all three angles in a triangle is always 180°.

So, we can set up the equation:

(x+35) + (2x-5) + (4x-15) = 180

Now, let's solve the equation to find the value of x.

Combine like terms:

7x + 15 = 180

Subtract 15 from both sides:

7x = 165

Divide both sides by 7:

x = 165/7

Simplify the fraction:

x = 23.57

Now that we have found the value of x, we can substitute it back into the expressions for angle A, B, and C to find their values.

Angle A = (23.57 + 35)° = 58.57°

Angle B = (2 * 23.57 - 5)° = 42.14°

Angle C = (4 * 23.57 - 15)° = 80.29°

Therefore, the three angles of triangle ABC are approximately:

Angle A = 58.57°

Angle B = 42.14°

Angle C = 80.29°

User MrGrigg
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