Question

A rectangular tank 5 metre long 4 metre wide and 2 m deep contain water to a depth of 1.5 metre. the water in his run off into an empty time that is 4 metre long and 3 metre wide what will be the depth of of water in a second tank

Answer 1

Answer:

2.5 meters

Explanation:

First, let's calculate the volume of the water in the first tank.

The volume of any cuboid (like the water in the tank) can be calculated by multiplying its length by its width by its height (or depth in the case of the tanks).

In the first tank, the water depth is 1.5 meter, and the tank is 5 meters long and 4 meters wide. So the volume of the water is:

`Volume = length * width * depth`

`Volume = 5 meters * 4 meters * 1.5 meters = 30 cubic meters`

This is the volume of the water that is being transferred to the second tank.

Now, let's calculate the depth of the water in the second tank after the water is transferred.

We know that the water will take up the same volume in the second tank, and we know that the second tank is 4 meters long and 3 meters wide.

We can find the depth by rearranging the formula for the volume of a cuboid to solve for height (or in this case, depth):

`Depth = Volume / (length * width)`

Substitute the values we know:

`Depth = 30 cubic meters / (4 meters * 3 meters) = 2.5 meters`

So the depth of the water in the second tank will be 2.5 meters.

Hope this helps! :)