92.2k views
0 votes
The average of 5 quantities is 6. the average of 3 of them is 8. what is the average of the remaining two numbers?

User Kumar V
by
8.4k points

1 Answer

4 votes

Explanation:

Let's denote the five quantities as A, B, C, D, and E. We know that the average of these five quantities is 6, which we can express as:

(A + B + C + D + E) / 5 = 6

Now, we're given that the average of 3 of these quantities (let's say A, B, and C) is 8:

(A + B + C) / 3 = 8

To find the average of the remaining two numbers (D and E), we can first find their total by subtracting the sum of A, B, and C from the total sum of all five quantities:

(A + B + C + D + E) - (A + B + C) = D + E

Now, we know the total sum of all five quantities is 5 times their average, which is 5 * 6 = 30. So:

30 - (A + B + C) = D + E

Since we already know that (A + B + C) / 3 = 8, we can substitute that in:

30 - 3 * 8 = D + E

30 - 24 = D + E

6 = D + E

Now, to find the average of D and E, we can divide their sum by 2:

(D + E) / 2 = 6 / 2 = 3

So, the average of the remaining two numbers (D and E) is 3.

User Vakus
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.