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The average of 5 quantities is 6. the average of 3 of them is 8. what is the average of the remaining two numbers?

User Kumar V
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Explanation:

Let's denote the five quantities as A, B, C, D, and E. We know that the average of these five quantities is 6, which we can express as:

(A + B + C + D + E) / 5 = 6

Now, we're given that the average of 3 of these quantities (let's say A, B, and C) is 8:

(A + B + C) / 3 = 8

To find the average of the remaining two numbers (D and E), we can first find their total by subtracting the sum of A, B, and C from the total sum of all five quantities:

(A + B + C + D + E) - (A + B + C) = D + E

Now, we know the total sum of all five quantities is 5 times their average, which is 5 * 6 = 30. So:

30 - (A + B + C) = D + E

Since we already know that (A + B + C) / 3 = 8, we can substitute that in:

30 - 3 * 8 = D + E

30 - 24 = D + E

6 = D + E

Now, to find the average of D and E, we can divide their sum by 2:

(D + E) / 2 = 6 / 2 = 3

So, the average of the remaining two numbers (D and E) is 3.

User Vakus
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