Answer:
0.34 mol S
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
11 g S
Step 2: Identify Conversions
[PT] Molar Mass of S - 32.07 g/mol
Step 3: Convert
- Set up:
![\displaystyle 11 \ g \ S((1 \ mol \ S)/(32.07 \ g \ S))](https://img.qammunity.org/2022/formulas/chemistry/high-school/rtzobz4olxpn0wej8fmji0rz1rc36rk358.png)
- Multiply/Divide:
![\displaystyle 0.343 \ mol \ S](https://img.qammunity.org/2022/formulas/chemistry/high-school/zu5bm79lvrq4a79cnba49gbw8ttp1lpe50.png)
Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
0.343 mol S ≈ 0.34 mol S