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A quarterback throws a football while standing at the very center of the field on the 50 yard line. the ball leaves his hand at a height of 6 ft and has initial velocity 0=47 35 23 ft/s. Assume an acceleration of 32 ft/s2 due to gravity and that the vector points down the field toward the endzone and the vector points to the sideline. the field is 150 ft in width and 300 ft in length. determine the position function that gives the position of the ball seconds after it is thrown. the ball is caught by a player 6 ft above the ground. assume the player is standing vertically with both toes on the ground at the time of reception. r(i) = _________________

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Final answer:

The initial velocity of the football relative to the quarterback requires additional information for an accurate calculation, as it involves combining the backward motion of the quarterback and the forward projectile velocity of the ball.

Step-by-step explanation:

The initial velocity of the football relative to the quarterback can be calculated by considering both the quarterback's backward movement and the relative forward velocity needed for the ball to reach the receiver who is 18.0 m downfield. Given that the quarterback is moving backward at a speed of 2.00 m/s and the ball needs to be thrown at an angle of 25.0° to be caught at the same height as it is released, we can use the principles of projectile motion to solve for the velocity. However, as the question does not provide enough information to account for the quarterback's movement in the velocity of the thrown football, we would need additional parameters to determine the relative velocity accurately.

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