To solve this problem, we need to use the concentration of the solution (25.0 ppm) and the amount of the solution (2000 g) to calculate the amount of lead present in the solution.
First, we need to convert the concentration from parts per million (ppm) to grams per gram (g/g). We can do this by dividing the ppm value by 1,000,000:
25.0 ppm = 25.0/1,000,000 g/g
Next, we can multiply the concentration (in g/g) by the amount of solution (in grams) to get the mass of lead present in the solution:
mass of lead = concentration x amount of solution
mass of lead = (25.0/1,000,000) x 2000
mass of lead = 0.050 g
Therefore, there are 0.050 grams of lead in 2000 grams of a 25.0 ppm solution of lead water waste.