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I need help with question 3 you don’t have to explain it I just need the answers thank you.

I need help with question 3 you don’t have to explain it I just need the answers thank-example-1
User Elena Filatova
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1 Answer

17 votes
17 votes
Answer:

Weight of the bag of sugar on the moon = 3.34 N

Weight of the bag of sugar on Venus = 18.09 N

Mass of the bag of sugar on the Earth = 2.04 kg

Mass of the bag of sugar on the moon = 2.04 kg

Mass of the bag of sugar on venus = 2.04 kg

Step-by-step explanation:

The weight of the object on the earth


\begin{gathered} W_E=4.50\text{ lb} \\ 1\text{ lb = }4.45\text{ N} \\ W_E=4.50\text{ }*4.45 \\ W_E=20.03N \end{gathered}

The acceleration due to gravity on the earth:


g_E=9.81m/s^2


\begin{gathered} W_E=m_Eg_E_{} \\ 20.03=m_E*9.81 \\ m_E=(20.03)/(9.81) \\ m_E=2.04\operatorname{kg} \end{gathered}

The mass of the bag of sugar on the earth = 2.04 kg

Note that the mass of the sugar is the same everywhere

Acceleration due to gravity on the moon is one-sixth of acceleration due to gravity on the earth


\begin{gathered} g_m=(1)/(6)g_E \\ g_m=(1)/(6)(9.81) \\ g_m=1.635 \end{gathered}

The weight of the bag of sugar on the moon is:


\begin{gathered} W_m_{}=m_mg_m_{} \\ W_m=2.04*1.635 \\ W_m=3.34N \end{gathered}

The acceleration due to gravity on the Venus is 0.904 times that of the earth


\begin{gathered} g_v=0.904g_E \\ g_v=0.904(9.81) \\ g_v=8.87m/s^2 \end{gathered}

The weight of the bag of sugar on the venus is:


\begin{gathered} W_v=m_vg_v \\ W_v=2.04(8.87) \\ W_v=18.09\text{ N} \end{gathered}

Mass of the bag of sugar on the Earth = 2.04 kg

Mass of the bag of sugar on the moon = 2.04 kg

Mass of the bag of sugar on venus = 2.04 kg

User Keith Otto
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