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The width of a rectangle is 4.25x - 2.5 feet and its length is 2.5x + 5 feet. Find the perimeter of the rectangle.

2 Answers

1 vote

Answer:


\boxed{\mathtt{Perimeter = 13.50x+5}}

Explanation:


\textsf{We are asked for the perimeter of the rectangle.}


\textsf{The Perimeter is simply the sum of the edges of a shape.}


\textsf{Because there's 4 sides to a Rectangle, we consider the Length and Width twice.}


\mathtt{Perimeter = Length + Length + Width + Width}


\textsf{Let's begin solving for the Perimeter.}


\large\underline{\textsf{Substitute:}}


\mathtt{Perimeter = 2(2.5x+5) + 2(4.25x-2.5)}


\large\underline{\textsf{Multiply:}}


\mathtt{Perimeter = 5x+10 + 8.50x-5}


\large\underline{\textsf{Combine Like Terms:}}


\boxed{\mathtt{Perimeter = 13.50x+5}}

User Qubix
by
8.4k points
3 votes

Answer:

13.5x + 5 feet is the perimeter of the rectangle.

Explanation:

Given: the width of a rectangle is 4.25x - 2.5 feet and its length is 2.5x + 5 feet. Find the perimeter of the rectangle.

First, the formula to finding the perimeter of a rectangle is 2(l+w).

Put in the length and width in the formula:

2(4.25x - 2.5 + 2.5x + 5)

Then simplify the expression in the parenthesis:

2(4.25x - 2.5 + 2.5x + 5)

2(4.25x+2.5x - 2.5+5)

2(6.75x + 2.5)

Then solve:

2(6.75x + 2.5)

2 * 6.75x + 2 * 2.5

= 13.5x + 5 feet is the perimeter of the rectangle.

User Gkrish
by
7.7k points

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