Question

The width of a rectangle is 4.25x - 2.5 feet and its length is 2.5x + 5 feet. Find the perimeter of the rectangle.

Answer 1

`\boxed{\mathtt{Perimeter = 13.50x+5}}`

Explanation:

`\textsf{We are asked for the perimeter of the rectangle.}`

`\textsf{The Perimeter is simply the sum of the edges of a shape.}`

`\textsf{Because there's 4 sides to a Rectangle, we consider the Length and Width twice.}`

`\mathtt{Perimeter = Length + Length + Width + Width}`

`\textsf{Let's begin solving for the Perimeter.}`

`\large\underline{\textsf{Substitute:}}`

`\mathtt{Perimeter = 2(2.5x+5) + 2(4.25x-2.5)}`

`\large\underline{\textsf{Multiply:}}`

`\mathtt{Perimeter = 5x+10 + 8.50x-5}`

`\large\underline{\textsf{Combine Like Terms:}}`

`\boxed{\mathtt{Perimeter = 13.50x+5}}`

Answer 2

13.5x + 5 feet is the perimeter of the rectangle.

Explanation:

Given: the width of a rectangle is 4.25x - 2.5 feet and its length is 2.5x + 5 feet. Find the perimeter of the rectangle.

First, the formula to finding the perimeter of a rectangle is 2(l+w).

Put in the length and width in the formula:

2(4.25x - 2.5 + 2.5x + 5)

Then simplify the expression in the parenthesis:

2(4.25x - 2.5 + 2.5x + 5)

2(4.25x+2.5x - 2.5+5)

2(6.75x + 2.5)

Then solve:

2(6.75x + 2.5)

2 * 6.75x + 2 * 2.5

= 13.5x + 5 feet is the perimeter of the rectangle.