Step-by-step explanation:
The concentration of sodium ions is equal to the concentration of NaOH in solution, which is: concentration of Na+ = concentration of NaOH concentration of Na+ = 0.10 M
Substituting the values for Ka, [CH3COO-], and [Na+] into the expression for Ka gives: Ka = [H+](0.051 M) / (0.10 M)
Solving for [H+] gives: [H+] = Ka x (0.10 M) / (0.051 M) [H+] = 1.96 x 10^-5 M
The pH of the solution is calculated using the equation: pH = -log[H+]
pH = -log(1.96 x 10^-5)
pH = 4.71
Therefore, the expected pH of the solution after 26.0 ml of NaOH has been added is 4.71.