Question

A 0.545L solution of KOH has a molarity of 2.84M. How many grams of KOH were used to make this aqueous solution?

Answer 1

Answer: 86.68 grams KOH or 86.7 g KOH to correct sig figs

Step-by-step explanation:

M= moles/L

moles = MXL

moles = 2.84 X 0.545 = 1.55 moles now multiply by the molar mass of KOH

which is 56 (from the periodic table) =