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3t-18=4(-3- 3/4t

solve for t

1 Answer

3 votes

Answer:

t = 1

Explanation:

I will assume that there is a parenthesis missing: the equation should read 3t-18=4(-3- 3/4t) and not 3t-18=4(-3- 3/4t

3t-18=4(-3- 3/4t)

3t-18= -12- 12/4t [Remove parentheses by multiplying each term by 4]

3t-6= - 3/t [Simplify]

3t^2-6t = -3 [Multiply both sides by t]

3t^2-6t +3 = 0

3(t^2-2t+1)=0

3(t-1)*(t-1) = 0

Two solutions, both the same value:

(t-1) = 0

t = 1

===

Does t=1 result in 0 for the equation?

3t-18=4(-3- 3/4t)

3(1)-18=4(-3- 3/4*(1))

3-18 = 4(-3-3/4)

-15 = 4(-3.75)

-15 = -15 YES

User John Conde
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