Answer:
t = 1
Explanation:
I will assume that there is a parenthesis missing: the equation should read 3t-18=4(-3- 3/4t) and not 3t-18=4(-3- 3/4t
3t-18=4(-3- 3/4t)
3t-18= -12- 12/4t [Remove parentheses by multiplying each term by 4]
3t-6= - 3/t [Simplify]
3t^2-6t = -3 [Multiply both sides by t]
3t^2-6t +3 = 0
3(t^2-2t+1)=0
3(t-1)*(t-1) = 0
Two solutions, both the same value:
(t-1) = 0
t = 1
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Does t=1 result in 0 for the equation?
3t-18=4(-3- 3/4t)
3(1)-18=4(-3- 3/4*(1))
3-18 = 4(-3-3/4)
-15 = 4(-3.75)
-15 = -15 YES