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Could use some help, think this might be right(new to precalculus Find dxdy . y= cosx1+ tanx7dxdy =
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Could use some help, think this might be right(new to precalculus Find dxdy . y= cosx1+ tanx7dxdy =
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Oct 7, 2024
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Could use some help, think this might be right(new to precalculus
Find dxdy . y= cosx1+ tanx7dxdy =
Mathematics
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Sander Van Keer
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Answer:
y= 1/cosx+7/tanx
dy/dx = 1secxtanx-cosec^2x
Rathnakara S
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Oct 13, 2024
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Rathnakara S
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