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Find the length of an edge of a square whose diagonals are of length 10cm

User Wittakarn
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Answer:

7.07 cm

Step by step explanation:

Let's use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

In a square, the diagonals are the longest sides and they are equal in length. Let x be the length of one of the sides of the square, then we can use the Pythagorean theorem to find x:

(diagonal)^2 = (side)^2 + (side)^2

10^2 = x^2 + x^2 (since the diagonal is the hypotenuse of a right triangle formed by the two sides of the square)

100 = 2x^2

x^2 = 50

x = sqrt(50) = 5 * sqrt(2)

Therefore, the length of an edge of the square is 5 * sqrt(2) cm (approximately 7.07 cm to two decimal places).
User MontDeska
by
8.2k points
1 vote

Answer:

Explanation:

Diagonals intersect at 90°.


x^2=5^2+5^2 (Pythagoras Theorem)


=50


x=√(50) cm =7.07 cm

Find the length of an edge of a square whose diagonals are of length 10cm-example-1
User Guy Royse
by
8.4k points

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