Answer:
the mass of Na2SO4 produced is 27.6 g.
Step-by-step explanation:
determine the balanced chemical equation for the reaction between NaCl and H₂SO4, and then use stoichiometry to calculate the mass of Na2SO4 produced.
The balanced chemical equation for the reaction is:
2 NaCl + H₂SO4 → Na2SO4 + 2 HCl
This equation tells us that 2 moles of NaCl react with 1 mole of H₂SO4 to produce 1 mole of Na2SO4.
First, we need to determine the number of moles of NaCl and H₂SO4 we have:
moles of NaCl = mass / molar mass = 48.0 g / 58.44 g/mol = 0.821 mol
moles of H₂SO4 = mass / molar mass = 19.0 g / 98.08 g/mol = 0.194 mol
Since H₂SO4 is the limiting reactant (it is present in less amount than required for complete reaction), we need to use the number of moles of H₂SO4 to calculate the number of moles of Na2SO4 produced:
moles of Na2SO4 = moles of H₂SO4 / 1 x (1 mole Na2SO4 / 1 mole H₂SO4) = 0.194 mol x (1/1) = 0.194 mol
Finally, we can use the molar mass of Na2SO4 to calculate the mass of Na2SO4 produced:
mass of Na2SO4 = moles of Na2SO4 x molar mass = 0.194 mol x 142.04 g/mol = 27.6 g
Therefore, the mass of Na2SO4 produced is 27.6 g.