63.5k views
21 votes
Plz help this is hard for me What is the area of this figure?

Plz help this is hard for me What is the area of this figure?-example-1
User Tjklemz
by
4.0k points

2 Answers

3 votes

Answer:

21 m^2

Step-by-step explanation:

(5*2) + (6*2) - (1*1) = 21

User Michael Harley
by
4.1k points
4 votes
Answer:
21m^2

Step-by-step explanation:
First, we can find the areas of the two large rectangles.
A=lw
A=2*6
A=12m^2

A=lw
A=2*5
A=10m^2

Now, we can find the area of the small square where the two rectangles overlap. We can tell that the side lengths of the square are all equal to 1 (we know this because the side lengths of the rectangles are 1 less on one side).
A=lw
A=1*1
A=1m^2

Now, we can subtract 1m^2 from either of the two rectangles’ area we solved for earlier.

12m^2-1m^2
=11m^2

Then, we can add this area to the area of the other rectangle.

11m^2+10m^2
=21m^2

I hope this helps!
User Nikhil J Joshi
by
4.0k points