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I kinda lost on this question, please help

I kinda lost on this question, please help-example-1

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Answer:

  • increasing: (0, π/2) ∪ (3π/2, 2π)
  • decreasing: (π/2, 3π/2)
  • relative maximum: (π/2, 1/2)
  • relative minimum: (3π/3, -1/2)

Explanation:

You want to know the intervals on which f(x) = sin(x)/(2+cos(x)²) is increasing and decreasing, and the relative extremes.

Derivative

The quotient rule can be used to find the derivative of f(x). Where the derivative is positive, the function is increasing.

f'(x) = ((2+cos(x)²)cos(x) +sin(x)(2cos(x)sin(x)))/(2+cos(x)²)²

f'(x) = (cos(x)(2 +cos(x)² +2sin(x)²)/(2+cos(x)²)²

f'(x) = cos(x)(3+sin(x)²)/(2+cos(x)²)²

We observe that the factors (3+sin(x)²) and (2+cos(x)²) are both positive for all x. This means the sign of the derivative will match the sign of cos(x).

Increasing

The function is increasing where cos(x) > 0, on the intervals ...

(0, π/2) ∪ (3π/2, 2π)

Decreasing

The function is decreasing where cos(x) < 0, on the interval ...

(π/2, 3π/2)

Relative maximum

The first derivative test tells us the function will have a relative maximum where the function goes from increasing to decreasing, at x = π/2. The function value at that point is ...

f(π/2) = sin(π/2)/(2 +cos(π/2)²) = 1/2

The relative maximum is at (π/2, 1/2).

Relative minimum

The first derivative test tells us the function will have a relative minimum where the function goes from decreasing to increasing, at x = 3π/2. The function value at that point is ...

f(3π/2) = sin(3π/2)/(2 +cos(3π/2)²) = -1/2

The relative minimum is at (3π/2, -1/2).

I kinda lost on this question, please help-example-1
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