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What is the molarity of a 0.5L sample of a solution that contains 60.0 g of sodium hydroxide (NaOH)

2 Answers

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Answer:

3 mol/L

Step-by-step explanation:

Molarity = No. of moles of solute/Volume of solution in L

What is the molarity of a 0.5L sample of a solution that contains 60.0 g of sodium-example-1
User Ebressert
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Answer:

The molarity of the solution is 3.0 M.

Step by Step Explanation:

To find the molarity of a solution, we need to know the number of moles of solute (in this case, NaOH) and the volume of the solution.

The first step is to calculate the number of moles of NaOH in the solution:

number of moles = mass / molar mass

The molar mass of NaOH is the sum of the atomic masses of the constituent atoms:

NaOH = Na + O + H = 23.0 g/mol + 16.0 g/mol + 1.0 g/mol = 40.0 g/mol

number of moles = 60.0 g / 40.0 g/mol = 1.5 mol

Next, we need to determine the volume of the solution in liters:

volume = 0.5 L

Finally, we can calculate the molarity (M) of the solution using the formula:

Molarity = moles of solute / volume of solution

Molarity = 1.5 mol / 0.5 L = 3.0 M

Therefore, the molarity of the solution is 3.0 M.
User George Polevoy
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