127k views
4 votes
I have 1.4 moles of a gas at a pressure of 4.7 atm and a volume of 23 liters, what is the temperature in Kelvin?

User Ray Johns
by
8.8k points

1 Answer

2 votes
Answer:

T = 232.01 K

Step by step solved:

We can use the Ideal Gas Law to solve for the temperature (T) in Kelvin:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

R = 0.0821 L·atm/(mol·K) (gas constant)

Substituting the given values into the Ideal Gas Law:

(4.7 atm)(23 L) = (1.4 mol)(0.0821 L·atm/(mol·K))(T)

Simplifying:

T = (4.7 atm x 23 L) / (1.4 mol x 0.0821 L·atm/(mol·K))

T = 232.01 K

Therefore, the temperature is approximately 232.01 Kelvin.
User Josep Vidal
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.