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I have 1.4 moles of a gas at a pressure of 4.7 atm and a volume of 23 liters, what is the temperature in Kelvin?

User Ray Johns
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Answer:

T = 232.01 K

Step by step solved:

We can use the Ideal Gas Law to solve for the temperature (T) in Kelvin:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

R = 0.0821 L·atm/(mol·K) (gas constant)

Substituting the given values into the Ideal Gas Law:

(4.7 atm)(23 L) = (1.4 mol)(0.0821 L·atm/(mol·K))(T)

Simplifying:

T = (4.7 atm x 23 L) / (1.4 mol x 0.0821 L·atm/(mol·K))

T = 232.01 K

Therefore, the temperature is approximately 232.01 Kelvin.
User Josep Vidal
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