190k views
4 votes
How to find the inverse for question B. Y = 4x^2-2

How to find the inverse for question B. Y = 4x^2-2-example-1

2 Answers

3 votes

Answer:

y=±(
√(x+2)/2)

Explanation:

User Jon Cahill
by
7.7k points
4 votes

Answer:

x = ± √((y + 2)/4)

Explanation:

To find the inverse of a function, we need to solve for x in terms of y.

Steps to find the inverse of y = 4x^2 - 2:

Replace y with x and x with y:

x = 4y^2 - 2

Solve for y:

x + 2 = 4y^2

(x + 2)/4 = y^2

± √((x + 2)/4) = y

Note that we have a ± sign because the square root of a positive number can have two values, one positive and one negative.

Therefore, the inverse of y = 4x^2 - 2 is:

x = ± √((y + 2)/4)

User George Mount
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories