Question

What are the values of limit of g (x) as x approaches 33 minus and limit of g (x) as x approaches 33 plus? limit of g (x) = negative 16 as x approaches 33 minus and limit of g (x) = negative 7 as x approaches 33 plus limit of g (x) = negative 15 as x approaches 33 minus and limit of g (x) = negative 6 as x approaches 33 plus limit of g (x) = negative 7 as x approaches 33 minus and limit of g (x) = negative 16 as x approaches 33 plus limit of g (x) = negative 6 as x approaches 33 minus and limit of g (x) = negative 15 as x approaches 33 plus.

Answer 1

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Explanation:

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Answer 2

Explanation:

The values of limit of g(x) as x approaches 33 minus and limit of g(x) as x approaches 33 plus are:

When limit of g(x) = -16 as x approaches 33 minus and limit of g(x) = -7 as x approaches 33 plus, we can say that g(x) has a jump discontinuity at x = 33. The limit from the left is different from the limit from the right, and hence the limit of g(x) as x approaches 33 does not exist.

When limit of g(x) = -15 as x approaches 33 minus and limit of g(x) = -6 as x approaches 33 plus, we can again say that g(x) has a jump discontinuity at x = 33. The limit from the left is different from the limit from the right, and hence the limit of g(x) as x approaches 33 does not exist.

When limit of g(x) = -7 as x approaches 33 minus and limit of g(x) = -16 as x approaches 33 plus, we can say that g(x) is continuous at x = 33, since the limit from the left is the same as the limit from the right, and both limits exist. Therefore, the limit of g(x) as x approaches 33 is -7.

When limit of g(x) = -6 as x approaches 33 minus and limit of g(x) = -15 as x approaches 33 plus, we can say that g(x) is continuous at x = 33, since the limit from the left is the same as the limit from the right, and both limits exist. Therefore, the limit of g(x) as x approaches 33 is -6.