41.7k views
3 votes
How do I find QE algebraically?

How do I find QE algebraically?-example-1

1 Answer

4 votes

Explanation:

this just means by solving an equation.

and that is simple to find.

as the diagonals of a parallelogram intersect each other at their midpoints, it means that both parts of the diagonal must be of equal length.

so,

x² + 9x = 4x + 6

x² + 5x - 6 = 0

the solution to a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = (-5 ± sqrt(5² - 4×1×-6))/(2×1) =

= (-5 ± sqrt(25 + 24))/2 =

= (-5 ± sqrt(49))/2 = (-5 ± 7)/2

x1 = (-5 + 7)/2 = 2/2 = 1

x2 = (-5 - 7)/2 = -12/2 = -6

x2 would make QE and SE negative so that did not make any sense.

that leaves us with x1 (x = 1) as valid solution.

QE = x² + 9x = 1² + 9×1 = 1 + 9 = 10

User Christoph Sommer
by
7.2k points