Question

8 abx - 8 ab ; 4 a²x - 4 a² ; 6 ax² - 6 ax = ?

Help please.

Answer 1

`\huge\boxed{\bf{Process:}}`

`{\boxed {\bold {8 abx - 8 ab ; 4 a^(2)x - 4 a^(2) ; 6 ax^(2) - 6 ax =}}}}}`

`{\boxed {\bold {8abx-8ab=8ab(x-1)}}}}}`

`{\boxed {\bold {4a^(2)x-4a^(2)=4a^(2)(x-1)}}}}}`

`{\boxed {\bold {6ax^(2)-6ax=6ax(x-1)}}}}}`

♣• Now in here we simplify or do the Least Common Multiple, (LCM).

`\frak{\pmb{\underline\green8}}`
`\frak{\pmb{\underline\green4}}`
`\frak{\pmb{\underline\green6}}`

`\frak{\pmb{\underline\green2}}`
`\frak{\pmb{\underline\green2}}`
`\frak{\pmb{\underline\green3}}`

`\frak{\pmb{\underline\green2}}`
`\frak{\pmb{\underline\green1}}`
`\frak{\pmb{\underline\green1}}`

`\frak{\pmb{\underline\green1}}`

♣• So the result of all this would be:

`\huge\boxed{\bf{2a\:(x-1)}}` ✅

➥ I hope I have helped you, greetings!

Atte: ✦TheGirlSad✦