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A material that has a fracture toughness of 50 MPa\cdotm1/2 and a yield strength of 1,000 MPa and s to be made into a large panel. If the panel is stressed to one-half the yield stress, what is the maximum central crack size that can be tolerated without catastrophic failure?

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Answer:

The maximum central crack size that can be tolerated without catastrophic failure is 0.0625 mm, calculated using the formula: crack size = 2*sqrt(Ft*K1c/σy), where Ft is the fracture toughness (50 MPa∙m1/2), K1c is the stress intensity factor (0.5*σy, where σy is the yield stress (1,000 MPa), and σy is the yield stress (1,000 MPa).

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