Answer: 55.9 meters per minute.
Explanation: To find the speed of the student, we need to divide the total distance traveled by the time taken to travel that distance.
The total distance traveled by the student is the sum of the distances traveled in the north and east directions.
Using Pythagoras theorem, we can find the total distance as:
distance = √((25 m)^2 + (50 m)^2)
distance = √(625 m^2 + 2500 m^2)
distance = √3125 m^2
distance = 55.9 m (rounded to one decimal place)
The time taken to travel this distance is given as one minute.
Therefore, the speed of the student is:
speed = distance / time
speed = 55.9 m / 1 min
speed = 55.9 m/min (rounded to one decimal place)
So, the speed of the student is 55.9 meters per minute.