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In the standard (x,y) coordinate plane, what is the distance between the points (4,-7) and (-1,5)

User Newalp
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1 Answer

3 votes

Answer:

Explanation:

To find the distance between two points in the coordinate plane, we can use the distance formula:

distance = √((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Applying the formula to the points (4,-7) and (-1,5), we get:

distance = √((-1 - 4)^2 + (5 - (-7))^2)

= √((-5)^2 + (12)^2)

= √(25 + 144)

= √169

= 13

Therefore, the distance between the points (4,-7) and (-1,5) is 13 units.

User Alireza
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