Question

Point X is the centroid of triangle ABC. If XZ = 3 meters, find the length of AX

Answer 1

Explanation:

AX = 2(XM)

where XM is the distance from the centroid to the

midpoint of BC.

Let Y be the midpoint of BC. Then, by the midpoint

theorem, we have:

YM = YZ=3/2 meters

Also, since X is the centroid, we have:

BX = CX= 2XM

So, we can write:

BC = BX+ CX = 4XM

But we also know that the centroid divides BC into two

parts in the ratio 2:1, so we have:

XM = BC/3

Substituting this into the expression for AX, we get:

AX = 2(XM) = 2(BC/3) = (2/3)BC

So we just need to find the length of BC. To do this, we

can use the Pythagorean theorem:

Answer 2

bing

Explanation:

the length is AX is 5.129 because i solved it like that