Answer:
0.556 moles of gas in this volume
there are approximately 3.35 x 10^23 molecules in this volume of gas.
Step-by-step explanation:
Given:
Volume of gas (V) = 13.4 L
Standard temperature (T) = 273 K
Standard pressure (P) = 1 atm
a. To determine the number of moles of gas in this volume, we can use the ideal gas law equation:
PV = nRT
where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin.
At STP, we know that the pressure is 1 atm and the temperature is 273 K. The gas constant R is 0.08206 L atm/mol K.
Plugging in the values, we get:
(1 atm) (13.4 L) = n (0.08206 L atm/mol K) (273 K)
Solving for n, we get:
n = (1 atm * 13.4 L) / (0.08206 L atm/mol K * 273 K) = 0.556 mol
Therefore, there are 0.556 moles of gas in this volume.
b. To determine the number of molecules in this volume of gas, we can use Avogadro's number, which tells us the number of molecules in one mole of a substance. Avogadro's number is approximately 6.02 x 10^23 molecules/mol.
Multiplying the number of moles by Avogadro's number, we get:
0.556 mol * (6.02 x 10^23 molecules/mol) = 3.35 x 10^23 molecules
Therefore, there are approximately 3.35 x 10^23 molecules in this volume of gas.