Answer:
9.06 × 10^22 aluminum atoms in 4.06 g of aluminum.
Step-by-step explanation:
To calculate the number of aluminum atoms in 4.06 g of aluminum, we can use the following steps:
Determine the molar mass of aluminum: 26.98 g/mol
Convert the given mass of aluminum to moles using the molar mass:
4.06 g Al × (1 mol Al / 26.98 g Al) = 0.1506 mol Al
Use Avogadro's number to convert the number of moles to the number of atoms:
0.1506 mol Al × (6.022 × 10^23 atoms/mol) = 9.06 × 10^22 Al atoms
Therefore, there are approximately 9.06 × 10^22 aluminum atoms in 4.06 g of aluminum.