Answer:
The only score that falls outside of this range is 35, so that is the outlier.
Explanation:
To find the mean of Allins test scores, we add up all the scores and divide by the number of scores:
Mean = (88+90+35+92+82+90)/6 = 77.83 (rounded to two decimal places)
To find the median, we need to arrange the scores in order from least to greatest:
35, 82, 88, 90, 90, 92
The median is the middle value, which in this case is 89.
To find the mode, we look for the value that appears most frequently. In this case, the mode is 90, since it appears twice.
To find the range, we subtract the lowest score from the highest score:
Range = 92 - 35 = 57
To identify the outlier in the data set, we can use the interquartile range (IQR) and the rule that any data point more than 1.5 times the IQR below the first quartile or above the third quartile is considered an outlier.
First, we need to find the quartiles:
Q1 (first quartile) = 80 (the median of the lower half of the data set)
Q3 (third quartile) = 91 (the median of the upper half of the data set)
IQR = Q3 - Q1 = 11
Any data point more than 1.5 times the IQR below Q1 or above Q3 is considered an outlier.
Lower outlier threshold = Q1 - 1.5(IQR) = 63.5
Upper outlier threshold = Q3 + 1.5(IQR) = 107.5
The only score that falls outside of this range is 35, so that is the outlier.