The volume of oxygen produced by the decomposition of hydrogen peroxide depends on the amount of hydrogen peroxide that decomposes.
A 10-volume solution of hydrogen peroxide means that 1 liter of the solution can produce 10 liters of oxygen at STP when completely decomposed.
The balanced chemical equation for the decomposition of hydrogen peroxide is:
2 H2O2 (aq) → 2 H2O (l) + O2 (g)
So, 2 moles of hydrogen peroxide will produce 1 mole of oxygen gas at STP.
One mole of a gas at STP occupies 22.4 L.
Therefore, the volume of oxygen gas produced by 1 liter of 10-volume solution of hydrogen peroxide is:
1 L H2O2 solution x (10 moles O2 / 2 moles H2O2) x (22.4 L/mole) = 112 L O2
So, the correct answer is not one of the options provided. The volume of oxygen at STP given by 1 liter of 10-volume solution of hydrogen peroxide is 112 L