Question

A juice drink contains 100 oz of concentrated juice and water, and is 28%

concentrated juice. If the drink is to be weakened to 20%, how much water must be added?

Actually answer. I will, and have, reported for people faking the asnwer or not answering at all. Please.

Answer 1

143

Explanation:

100 oz is 28 % of the drink

So total volume of the drink = 357 oz.

A drink that of 100 oz juice and is 20% juice has a volume of 500 oz.

So, we need to add 500 - 357

= 143 oz water.

Answer 2

Answer: We need to add 40 ounces of water to the 100 oz of concentrated juice and water to obtain a new mixture that is 20% concentrated juice.

Explanation:

We can begin by setting up an equation based on the given information.

Let's say we need to add x ounces of water to the 100 oz of concentrated juice and water to obtain the new 20% mixture.

The amount of pure juice in the original 100 oz mixture is 28% of 100 oz, which is 0.28(100) = 28 oz.

After x ounces of water are added, the total volume of the mixture becomes 100 + x oz. The amount of pure juice remains the same at 28 oz. We want to find the amount of water that needs to be added to reach a concentration of 20%.

Setting up the equation:

0.20(100 + x) = 28

Expanding and simplifying:

20 + 0.20x = 28

0.20x = 8

x = 40